A stone is thrown vertically upwards from the top of a tower `64m` high according to the law of motion given by `s=48t-16t^(2)`. The greatest height attained by the stone above ground is

A stone is thrown vertically upwards from the top of a tower 64 metres high according to the law s=48tg-16t^(@) . The greatest height attained by the stone above the ground is

A stone is thrown vertically upwards from the top of a tower 64 metres high according to law s=48t-16t^(2) . The greatest height attained by the stone above the ground is

A stone is thrown vertically upwards and the height x ft, reached by the stone in t seconds is given by x=80t-16t^(2) . The stone reaches the maximum height in

A stone is project vertically upward from the top of a tower of height 60 m. The stone moves according to the law S=(10)t-5t^(2) , where S is in meters and t in second The maximum height , reached by the stone , from the ground , is

A stone is thrown up vertically and the height x feet reached by it in time t seconds is given by x=80t-16t^(2) . The stone reaches the maximum height in time (seconds)

A stone is thrown vertically up and the height s reached in time t is given by s=80t-16t^2 . The stone reaches the maximum height in time t =

A stone is thrown upwards from the top of tower 85 m high , reaches the ground in 5 s. find (i) the greatest height it reaches above the ground (ii) the velocity with which it reaches the ground and (iii) the time taken to reach the maximum height . Take g = 10ms ^(-2) ?

A stone is thrown vertically upwards from the top of a building, with a speed of 14.7m/s. if it returns to the earth in 8s, calculate the height of the building.

A stone thrown upwards from the top of a tower 85 m high, reaches the ground in 5s. Find the greatest height above the ground.Take g = 10 ms^(-2)