Displacement Of A Particle In Nth Second Of Motion

Displacement Of Particle In Nth Second

Give the expression to find out the displacement of a particle in nth second.

A particle starts from rest with uniform acceleration a . Its velocity after n seconds is v . The displacement of the particle in the two seconds is :

A particle is projected vertically upwards from ground with an initial speed of 57m/s .If acceleration due to gravity is taken to be equal to 10m/ s^(2) ,then the displacement of the particle in the sixth second of its motion will be?

A particle starts moving from rest such that it has uniform acceleration a_0 during the 1st second of motion, uniform acceleration (a_0)/(2) during the 2nd second of motion, uniform acceleration (a_0)/(4) during the 3rd second of motion, and so on, such that it has uniform acceleration (a_0)/(2^(n-1)) during the nth second of motion If the displacement of the particle during the 5th second of motion is D_5 =(Ka_0)/(32) , the value of K is

A particle is moving in a straight line under constant acceleration of 4 m//s^(2) . If its velocity at t=0 is 10 m//s, the displacement of particle in the 5^(th) second of its motion is

Figure shows the position time graph for a particle in one dimensional motion. What is the displacement of the particle in first 4 seconds ?

The velocity-time graph of a particle moving along a straight line is shown in the figure-given below The displacement of the particle in 5 second is

The velocity - time graph of a particle moving along a straight line is shown in the figure given below The displacement of the particle in 5 second is

The total energy of a partical executing simple harmonic motion of period 2pi secon is 10,240ert. The displacement of the particle at pi//4 second is 8sqrt(2)cm . Calculate the amplitutde of motion and mass of the particle