Projection From A Tower

Projectile from Tower

A particle is projected from a tower as shown in figure, then find the distance from the foot of the tower where it will strike the ground. (g=10m//s^(2))

Two particles are projected from a tower horizontally in opposite directions with velocities 10 m//s and 20 m//s . Find the time when their velocity vectors are mutually perpendicular. Take g=10m//s^2 .

Two balls of equal mass are projected from a tower simultaneously with equal speeds. One at angle theta above the horizontal and the other at the same angle theta below the horizontal. The path of the center of mass of the two balls is

A particle is projected from a tower of height 25 m with velocity 20sqrt(2)m//s at 45^@ . Find the time when particle strikes with ground. The horizontal distance from the foot of tower where it strikes. Also find the velocity at the time of collision.

Two particles of different masses projected from a tower with same speed horizontally but in opposite directioin. One particle of mass 3kg follows a path y=-(x^(2))/20 and C.O.M. of the system also follows a path y=-5/4x^(2) in the same direction as 3kg particle. Then find unknonw mass (in kg)

Particle projected from tower fo heigh 10m as shown in figure. Find the time (in sec) after which particle will hit the ground.

A particle is projected horizontally from a tower with velocity u towards east. Wind provides constant horizontal acceleration (g)/(2) towards west. If particle strikes the ground vertically the then :