CASE 1 - HORIZONTAL PROJECTILE FROM BUILDING ( OR CERTAIN HEIGHT)

CASE 2 - PROJECTILE FROM BUILDING AT CERTAIN ANGLE

The horizontal range (R ) of a projectile becomes (R + 2 H) from R due to a wind in horizontal direction. Here H is the maximum height reached by the projectile. What constant horizontal acceleration is imparted by the wind ?

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A projectile attains a certain maximum height H1 when projected from earth. If it is projected at the same angle and with the same initial speed from the moon, where the acceleration due to gravity is one-sixth that on earth, the maximum height attended by the projectile is H_2 . THe ratio H_2//H_1 is:

Assertion: In projectile motion, when horizontal range is n times the maximum height, the angle of projection is given by tan theta=(4)/(n) Reason: In the case of horizontal projection the vertical increases with time.

Time Of Flight And Range For Horizontal Projectile From Building

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