Turning Of Vehicle On Banked And Frictional Circular Road

Turning Of Vehicle On Frictional Circular Road

What is the need of banking a circular road ?

A car is moving with speed v and is taking a turn on a circular road of radius 10 m. The angle of banking is 37^(@) . The driver wants that car does not slip on the road. The coefficient of friction is 0.4 (g = 10 m//sec^(2)) The speed of car for which no frictional force is produced is :

Circular Turnings On Road|By Friction Only|By Banking Of Roads Only|By Friction & Banking Of Roads

Questions|Circular Motion In Horizontal Plane|Questions|Circular Turnings On Road|By Friction Only|By Banking Of Roads Only|By Friction And Banking Of Roads Both

Questions|Circular Motion In Horizontal Plane|Questions|Circular Turnings On Road|By Friction Only|By Banking Of Roads Only|By Friction And Banking Of Roads Both

Questions|Circular Motion In Horizontal Plane|Questions|Circular Turnings On Road|By Friction Only|By Banking Of Roads Only|By Friction And Banking Of Roads Both

Keeping the angle of banking, if the radius of curvature is made four times, the percentage increase in the maximum speed with which a vehicle can travel on a circular road is

A car is moving along a banked road laid out as a circle of radius r . (a) What should be the banking angle theta so that the car travelling at speed v needs no frictional force from tyres to negotiate the turn ? (b) The coefficient of friction between tyres and road are mu_(s) = 0.9 and mu_(k) = 0.8 . At what maximum speed can a car enter the curve without sliding toward the top edge of the banked turn ?

Revision|Questions|Dynamics Of Circular Motion - Circular Turning On Roads|By Friction|By Banking Of Roads Only|Friction And Banking Of Road Both|Conical Pendulum|Death Well Or Rotor|Question|OMR