Wet On System Of Particals

Assertion: The change in kinetic energy of a partical is equal to the work done on it by the net force. Reason: Change in kinetic energy of partical is equal to the work done in case of a system of one partical.

In a hypothetical system , a partical of mass m and charge -3 q is moving around a very heavy partical chaRGE q . Assume that Bohr's model is applicable to this system , then velocuity of mass m in the first orbit is

If the net work done by external force on a partical is zero which is the following statement about the partical must be true?

The potential energy of a partical veries with distance x as shown in the graph. The force acting on the partical is zero at

The adojoining diagram showns the velocity versus time plot for a partical . The work done by the force on the partical is positive from

A partical is performing SHM of amplitude 'A' and time period 't'. Find the time taken by the partical to go from 0 to A//2 .

A partical executing simple harmonic motion has amplitude of 1 m and time period 2 s At t = 0 , net force on the partical is zero. Find the equation of displacement of the partical.

The kinetic energy of partical moving along a circule of radius R depends upon the distance covered S and given by K = aS where a is a constant. The the force acting on the partical is

i.The acceleration versus time graph of a partical SHM is shown in the figure . Plot the displacement versus time graph ii. The frection of oscillation is…….. iii. The displacement amplitude is ……… iv. At t = 0 , the velocity of the partical is ...... v. The kinetic energy of the partical is maximum at t = ....... and t = ...... vi. The potential energy is maximum at t = ....... : t = ..... ans t = .........