Efficiency Of Carnot Cycle

A Carnot reversible engine converts 1//6 of heat input into work. When the temperature of the sink is redused by 62 K, the efficiency of Carnot’s cycle becomes 1//3 . The sum of temperature (in kelvin) of the source and sink will be

The efficiency of a Carnot cycle is 1//6 . By lowering the temperature of sink by 65 K , it increases to 1//3 . The initial and final temperature of the sink are

The efficiency of a Carnot cycle is 1//6 . If on reducing the temperature of the sink by 65^@C , the efficiency becomes 1//3 , find the source and sink temperatures between which the cycle is working.

A Carnot reversible engine converts 1//6 of heat input into work . When the temperature of the sink is reduced by 62 K, the efficiency of carnot's cycle becomes 1//3 . The temperature of the source and sink will be

The efficiency of a carnot cycle is 1//6 . On decreasing the tempertaure of the sink by 65^(@)C , the efficiency increases to 1//3 .Calculate the tempretaure of source and sink .

The efficiency of a carnot cycle is 1/8 On decreasing the temperature of the sink by 65^(@) C, the efficiency increases to 1/3 . Calculate the temperature of source (in C^(@)

In which case will the efficiency of a carnot cycle be higher : When the hot body temperature is increased by Delta T , or when the cold body temperature is decreased by the same magnitude ?