Slection Of Gaussian Surface

Selection Of Gaussian Surface

A uniformly charged conducting sphere is having radius 1 m and surface charge density 20" Cm"^(-2) . The total flux leaving the Gaussian surface enclosing the sphere is

A spherical Gaussian surface encloses a charge of 8.85xx10^(-8) C (i) Calculate the electric flux passing through the surface (ii) If the radius of Gaussian surface is doubled, how would the flux change ?

What is the nature of Gaussian surface involved in Gauss's law of electrostatics?

A+q_(1) charge is at centre of an imaginary spherical Gaussion surface 'S', and -q_(1) charge is placed nearby this +q_(1) charge inside 'S'. A charge +q_(2) is located outside this Gaussian surface. Then electric field on Gaussian surface will be :

Can Gauss's law in electrostatics tell us exactly where the charge is located within the Gaussian surface ?

Assertion:- In a given situation of arrangement of charges, an extra charge is placed outside the Gaussion surface. In the Gauss Theroem ointvecEdvecs=(Q_(in))/(epsilon_(0))Q_(in) remains unchanged whereas electric field vecE at the site of the element is changed. Reason:- Electric field vecE at any point on the Gaussian surface is due to inside charge only.