Selection Of Gaussian Surface

Slection Of Gaussian Surface

Assertion(A):If Gaussian surface does not enclose any charge then vec(E) at any point on the Gaussian surface must be zero. Assertion(R ):No net charge is enclosed by Gaussians surface,so net flux passing through the surface is zero.

A uniformly charged conducting sphere is having radius 1 m and surface charge density 20" Cm"^(-2) . The total flux leaving the Gaussian surface enclosing the sphere is

A Gaussian surface encloses a proton p. The electric field at any point on the surface is vec€ . The flux linked with the Gaussian surface is phi . STATEMENT-1 : When an electron is kept close to this system outside the Gaussian surface, the flux linked with the surface would change. and STATEMENT-2 : The presence of electron will alterthe electric field on the gaussian surface.

A spherical Gaussian surface encloses a charge of 8.85xx10^(-8) C (i) Calculate the electric flux passing through the surface (ii) If the radius of Gaussian surface is doubled, how would the flux change ?

What is the nature of Gaussian surface involved in Gauss's law of electrostatics?

In Gauss' s theorem underset(s)oint"Eds"=(q)/(epsilon_(0)) The surface integral is evaluated by choosing a closed surface called the Gaussian surface. Here