Charged Conducting Sphere

consider a neutral conducting sphere of radius a with a spherical cavity of radius b . A charged conducting sphere of radius c is placed in cavity . Centre of this sphere coincide with centre of cavity charge on the inner sphere is q total self energy of this arrangement is:

Two charged conducting spheres of radill a and b are connected to eachother by a wire. What is the ratio of electric fields at the surface of two spheres ? Use the result obtained to explain why charge density on the sharp and pointed ends of a conducter is higher than on its fatter portions ?

A drop of water of mass m falls away from the bottom of charged conducting sphere of radius R, carrying with it a charge q_(1) and leaving the sphere a uniformly distributed charge q_(2) . The kinetic energy of the drop after it has fallen height h is -

(a) Using Gauss's law, derive an expression for the electric field intensity at any point outside a uniformly charged thin spherical shell of radius R and charge density sigma C//m^(2) . Draw the field lines when the charge density of the sphere is (i) positive, (ii) negative. (b) A uniformly charged conducting sphere of 2.5 m in diameter has a surface charge density of 100 mu C//m^(2) . Calculate the (i) charge on the sphere (ii) total electric flux passing through the sphere.

(a) Two charged bodies, A and B are suspended from a fixed point with the help of silk threads as shown in the figure. If A is positively charged can we identify the nature of charge on 'B' ? (b) A negatively charged conducting sphere A and a neutral sphere B are kepton insulating stands and brought cose to each other. The charge distri-bution is as shown in the figure. Is B charged ? What type of force exists between A and B ?

A drop of water of mass 18xx10^-3 g falls away from the bottom of a charged conducting sphere of radius 20 cm, carrying with it a charge of 10^(-9)C and leaving on the sphere a uniformly distributed charge of 2.5xx10^(-6)C . What is the speed of the drop after it has fallen 30 cm? (4piepsi_(0))^(-1)=9xx10^(9)JmC^(-2)