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Galvanometer

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If a galvanometer is connected in series with a high resistance so that potential drop across the galvanometer is 1/n th of the total applied voltage, then show that the combined resistance of the galvanometer and the series resistor is n times the resistance of the galvanometer i.e.,

In a galvanometer there is a deflection of 10 divisions per 50 mA . The internal resistance of the galvanometer is 60Omega . If a shunt of 2*5Omega is connected to the galvanometer and there are 50 divisions in all on the scale of galvanometer what maximum current can this galvanometer read?