MOTION OF CHARGED PARTICLE IN UNIFORM MAGNETIC FIELD WHEN V AND B ARE AT SOME ANGLE THAN 0, 90 AND 180

MOTION OF CHARGED PARTICLE IN UNIFORM MAGNETIC FIELD WHEN V AND B ARE PERPENDICULAR)

MOTION OF CHARGED PARTICLE IN UNIFORM MAGNETIC FIELD WHEN V AND B ARE PARALLEL/ANTIPARALLEL)

Motion OF a Charged Particle in Uniform Magnetic Field || Radius OF Circle || Time Period & Frequency || Examples

Motion Of An Particle In Uniform Magnetic Field|Equilibrium Of Charge Particles In Uniform Electric Field|Questions

Questions|Motion Of Charge Particle In Uniform Magnet Field |Velocity is Parallel To Magnetic Field

Force on A Charged Particle|Uniform CM Of A Charged Particle|Second Type Of Motion|Motion Of A Charged Particle In a Limited Regoin Field

The path of a charged particle in a uniform magnetic field depends on the angle theta between velocity vector and magnetic field, When theta is 0^(@) or 180^(@), F_(m) = 0 hence path of a charged particle will be linear. When theta = 90^(@) , the magnetic force is perpendicular to velocity at every instant. Hence path is a circle of radius r = (mv)/(qB) . The time period for circular path will be T = (2pim)/(qB) When theta is other than 0^(@), 180^(@) and 90^(@) , velocity can be resolved into two components, one along vec(B) and perpendicular to B. v_(|/|)=cos theta v_(^)= v sin theta The v_(_|_) component gives circular path and v_(|/|) givestraingt line path. The resultant path is a helical path. The radius of helical path r=(mv sin theta)/(qB) ich of helix is defined as P=v_(|/|)T P=(2 i mv cos theta) p=(2 pi mv cos theta)/(qB) A charged particle moves in a uniform magnetic field. The velocity of particle at some instant makes acute angle with magnetic field. The path of the particle will be

As a charged particle 'q' moving with a velocity vec(v) enters a uniform magnetic field vec(B) , it experience a force vec(F) = q(vec(v) xx vec(B)). For theta = 0^(@) or 180^(@), theta being the angle between vec(v) and vec(B) , force experienced is zero and the particle passes undeflected. For theta = 90^(@) , the particle moves along a circular arc and the magnetic force (qvB) provides the necessary centripetal force (mv^(2)//r) . For other values of theta (theta !=0^(@), 180^(@), 90^(@)) , the charged particle moves along a helical path which is the resultant motion of simultaneous circular and translational motions. Suppose a particle that carries a charge of magnitude q and has a mass 4 xx 10^(-15) kg is moving in a region containing a uniform magnetic field vec(B) = -0.4 hat(k) T . At some instant, velocity of the particle is vec(v) = (8 hat(i) - 6 hat(j) 4 hat(k)) xx 10^(6) m s^(-1) and force acting on it has a magnitude 1.6 N Motion of charged particle will be along a helical path with

As a charged particle 'q' moving with a velocity vec(v) enters a uniform magnetic field vec(B) , it experience a force vec(F) = q(vec(v) xx vec(B)). For theta = 0^(@) or 180^(@), theta being the angle between vec(v) and vec(B) , force experienced is zero and the particle passes undeflected. For theta = 90^(@) , the particle moves along a circular arc and the magnetic force (qvB) provides the necessary centripetal force (mv^(2)//r) . For other values of theta (theta !=0^(@), 180^(@), 90^(@)) , the charged particle moves along a helical path which is the resultant motion of simultaneous circular and translational motions. Suppose a particle that carries a charge of magnitude q and has a mass 4 xx 10^(-15) kg is moving in a region containing a uniform magnetic field vec(B) = -0.4 hat(k) T . At some instant, velocity of the particle is vec(v) = (8 hat(i) - 6 hat(j) 4 hat(k)) xx 10^(6) m s^(-1) and force acting on it has a magnitude 1.6 N If the coordinates of the particle at t = 0 are (2 m, 1 m, 0), coordinates at a time t = 3 T, where T is the time period of circular component of motion. will be (take pi = 3.14 )

A charged particle with charge to mass ratio ((q)/(m)) = (10)^(3)/(19) Ckg^(-1) enters a uniform magnetic field vec(B) = 20 hat(i) + 30 hat(j) + 50 hat(k) T at time t = 0 with velocity vec(V) = (20 hat(i) + 50 hat(j) + 30 hat(k)) m//s . Assume that magnetic field exists in large space. During the further motion of the particle in the magnetic field, the angle between the magnetic field and velocity of the particle