WAVELENGTH OF PHOTON EMITTED IN DE- EXCITATION

Both the nucleus and the atom of some element are in their respective first excited states. They get de-excited by emitting photons of wavelengths lambda_(N) ,lambda_(A) respectively. The ratio (lambda_(N))/(lambda_(A)) is closest to :

An excited nucleus emits a gamma-ray photon with energy of 2.45 MeV. (a) What is the photon frequency? (b) what is the photon wavelength?

An excited state of H atom emits a photon of wavelength lamda and returns in the ground state. The principal quantum number of excited state is given by:

Does a photon have a de-Broglie wavelength ? Explain.

More Questions On Photon Theory||de-Broglie Wavelength

The ground state energy of hydrogen atom is -13.6eV . If the electron jumps to the ground state from the 3^("rd") excited state, the wavelength of the emitted photon is

A unielectronic species is in some excited state 'A' and on absorbing a photon of energy 'x' eV gets promoted to a new state 'B' . On de-excitation back to the ground state a total of 10 different wavelengths were emitted in which seven have energy greater than 'x' eV . What will be the ionisation energy ?