If the degree of ionization of water be `1.8xx10^(-9)` at `298 K`. Its ionization constant will be

If the degree of ionization of water is 1.8xx10^(-9) at 298K . Its ionization constant will be

The degree of dissociation of water is 1.8 xx10^(-9) at 298 K . Calculate the ionization constant and Ionic product of water at 298 K .

The degree of dissociation of water is 1.8 xx 10^(-9) at 298 K. Calculate the ionisation constant and ionic product of water at 298 K

Calculate the degree of ionization of pure water at 25^@C .

What is the pH of 0.001 M aniline solution? The ionization constant of aniline 4.27xx10^(-10) . Calculate the degree of ionization of aniline in the solution. Also calculate the ionization constant of the conjustant acid of aniline.

What is the pH of 0.001 M aniline solution? The ionization constant of aniline 4.27xx10^(-10) . Calculate the degree of ionization of aniline in the solution. Also calculate the ionization constant of the conjustant acid of aniline.

The ionization constant of aniline is 4.3xx10^(-10) (i)Calculate the pH of 0.001 M aniline solution , (ii)Calculate the degree of ionization of aniline in the solution. (iii)Calculate ionization constant of the conjugate acid of aniline.