A string fixed at both ends, oscillate in 4th harmonic. The displacement of particular wave is given as `Y=2Asin(5piX)cos(100pit)`. Then find the length of the string?

A string fixed at both the ends is vibrating in two segments. The wavelength of the corresponding wave is

The Equation for the vibration of a string fixed at both ends vibrating in its third harmonic is given by y = 2 sin (0.6x) cos (500 pi t) (x, y are in cm t is in sec). The length of the string is

A rope, under tension of 200N and fixed at both ends, oscialltes in a second harmonic standing wave pattern. The displacement of the rope is given by y=(0.10)sin ((pix)/(3)) sin (12 pit) , where x=0 at one end of the rope, x is in metres and t is in seconds. Find the length of the rope in metres.

A rope, under tension of 200N and fixed at both ends, oscialltes in a second harmonic standing wave pattern. The displacement of the rope is given by y=(0.10)sin ((pix)/(3)) sin (12 pit) , where x=0 at one end of the rope, x is in metres and t is in seconds. Find the length of the rope in metres.

The equation for the vibration of a string fixed at both ends vibrating in its third harmonic is given by y=2cm sin[(0.6cm^-1)x]cos[(500pis^-1)t] . The length of the string is

A stretched string fixed at both end has n nods, then the lengths of the string is

The equation for the vibration of a string fixed at both ends vibrating in its second harmonic is given by y=2sin(0.3cm^(-1))xcos((500pis^(-1))t)cm . The length of the string is :

The equation for the vibration of a string fixed at both ends vibrating in its second harmonic is given by y=2sin(0.3cm^(-1))xcos((500pis^(-1))t)cm . The length of the string is :

If a string fixed at both ends, vibrates in its fourth harmonic, the wavelength is 15 cm. What is the length of the string ?