
Let us assume a triangle `ABC` such that the sides are as `AB > AC`.
Now, take a point `P` on line `AB` such that `AP = AC`. Join the two points `C` and `P` to set `CP`. Let us assume angle `APC` is `x` and angle `BCP` is `y`.
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We know that `AP = AC`.
If two sides are equal in a triangle, then the angles opposite to the sides are equal. Applying this condition to the triangle `APC`, we get the angle `APC` and angle `ACP`, all equal. As angle `APC` is `x`,
we get the angle `ACP` also `x`.
Mathematically, we write these steps as follows:
`/_ACP=/_APC`
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