Theorem 10.3 : The perpendicular from the centre of a circle to a chord bisects the chord.
Text Solution
Verified by Experts
In `/_\OXA` and `/_\OXB`,
`/_OXA=/_OXB` (perpendicular angles)
`OA=OB` (Radius)
`OX-=OX` (Common)
By RHS rule, `/_\OXA` and `/_\OXB` are congruent.
`AX=BX` (CPCT)
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