In a series LR circuit, the voltage drop across inductor is 8 volt and across resistor is 6 volt. Then voltage applied and power factor of circuit respectively are:

In series LCR circuit voltage drop across resistance is 8V, across inductor is 6V and across capacitor is 12V. Then

In series LCR circuit voltage drop across resistance is 8V, across inductor is 6V and across capacitor is 12V. Then

In the above circuit, the voltage drop across the resistance (R) is

In LCR series circuit source voltage is 120 volt and voltage in inductor 50 volt and resistance is 40 volt then determine voltage in capacitor.

In LCR series circuit source voltage is 120 volt and voltage in inductor 50 volt and resistance is 40 volt then determine voltage in capacitor.

In a LR circuit, the AC source has voltage 220V and potential difference across the resistor is 176V .The power factor of the circuit is

Find the voltage drop across 18 Omega resistor in the given circuit.

In an LCR series circuit the voltages across R,L and C at resonance are 40 V and 60V respectively the applied voltage is .

In a series LCR circuit, rms voltage across inductor and capacitor are found ot be 8 V and 5 V respectively. If applied voltage is 5 volts, then what is rms voltage across resistance in volts ?