If `f:R->R` and `g:R->R` is given by f(x) =|x| and g(x)=[x] for each `x in R` then `{x in R:g(f(x))le f(g(x))}`

If f : R to R and g: R to R are given by f(x) =|x| and g(x) =[x] for each x in R , then {x in R: g(f(x)) le f(g(x))} =

If f : R rarr R and g: R rarr R are given by f(x)=|x| and g(x)={x} for each x in R , then |x in R : g(f(x)) le f(g(x))}=

If f:R rarr R and g:R rarr R are defined by f(x)=x-[x] and g(x)=[x] is x in R then f{g(x)}

If f:R rarr R and g:R rarr R given by f(x)=x-5 and g(x)=x^(2)-1, Find fog

If f: R to R and g: R to R are defined by f(x) =x-[x] and g(x) =[x] AA x in R, f(g(x)) =

If f:R to R and g:R to R are given by f(x)=sin x and g(x) =x^(5) , then find gof(x).

Write fog if f:R rarr R and g: R rarr R is given by f(x) = | x| and g(x) = |5x - 2|.

If f : R -> R and g : R -> R defined f(x)=|x| and g(x)=[x-3] for x in R [.] denotes the greatest integer function then {g(f(x)):(-8)/(5)ltxlt(8)/(5)} =