Home
Class 11
PHYSICS
The equation of a longitudinal stationar...

The equation of a longitudinal stationary wave in a metal rod is given by, `y = 0.002 sin "(pix)/(3) sin 1000pit`, where `x` & `y` are in `cm` and `t` is in seconds. If maximum change in pressure (the maximum tensile stress) at the point `x = 2 cm` is `(1)/(n) xx 10^(-3) "dyne"//"cm"^(2)`, Find `n`. Given young's modulus of the material is `(3)/(8pi) "dynes"//"cm"^(2)`.

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of a stationary wave in a metal rod is given by y=0.92 sin.(pix)/(3)sin1000t , where x is in cm and t is in second. The maximum tensile stress at a point x = 1 cm is (npi)/(3)xx10^(8)" dyne cm"^(-2) . What is the value of n? [Young's modulus of the material of rod is =8xx10^(11)" dyne cm"^(-2) ]

The equation of a stationary wave in a metal rod is given by y=0.92 sin.(pix)/(3)sin1000t , where x is in cm and t is in second. The maximum tensile stress at a point x = 1 cm is (npi)/(3)xx10^(8)" dyne cm"^(-2) . What is the value of n? [Young's modulus of the material of rod is =8xx10^(11)" dyne cm"^(-2) ]

The equation of stationary wave along a stretched string is given by y=5 sin (pix)/(3) cos 40 pi t , where x and y are in cm and t in second. The separation between two adjacent nodes is

A stationary wave is given by y = 5 sin (pi x)/(3) cos 40 pi t where x and y are in cm and t is in seconds What is the distance between two successive nodes

The equation of a transverse wave travelling in a rope is given by y = 5 sin (4t - 0.02 x) , where y and x are in cm and time t is in second. Then the maximum transverse speed of wave in the rope is

The equation of a transverse wave travelling on a rope is given by y =10 sin pi (0.01xx -2.00t) where y and x are in cm and t is in seconds. The maximum transverse speed of a particle in the rope is about