0 = 18 - 220 + 1 (p) 0 = 1g + 220 - I (q) 0 = 18 – 220 - VOT 0 = 18 +220 + 1 (e) is such that A2 = 1,then ^ = VII 'S WASH асата олтт

If a^(2) + (1)/(a^(2)) = 18 and a ne 0 , find: a- (1)/(a)

If a^(2) + (1)/(a^(2)) = 18 and a ne 0 , find: a^(3)- (1)/(a^(3))

If a geyser is rated at 1.5 kW. - 220 V, what does it mean?

(7^-1-18^-1)^0 =______

Two electric bulbs rated 25 W , 220 V and 100 W , 220 V are connected in series across a 220 V voltage source . The 25 W and 100 W bulbs now draw P_(1) and P_(2) powers , respectively.

Two heaters rated 220 V / 1 kW and 220 V / 3 kW are connected in parallel across a 220V source. Which of these will heat up faster? Explain why.

An electric bulb rated 220V, 100W is connected to a source of 220 (0.8)V then actual power will be