`(a^(2)+b^(2))=`

Simplify: (a^(2)-(b-c)^(2))/((a+c)^(2)-b^(2))+(b^(2)-(a-c)^(2))/((a+b)^(2)-c^(2))+(c^(2)-(a-b)^(2))/((b+c)^(2)-a^(2))

Using formula let's show that. (a+2b)^2 + (a-2b)^2 = 2(a^2 + 4b^2)

x=sqrt(a^2cos^2alpha+b^2sin^2alpha)+sqrt(a^2sin^2alpha+b^2cos^2alpha) then x^2=a^2+b^2+2sqrt(p(a^2+b^2)-p^2) , where p is equal to (a) a^2cos^2alpha+ b^2sin^2alpha (b) a^2sin^2alpha+b^2cos^2alpha (c) (1/2)(a^2+b^2+(a^2-b^2)cos2alpha) (d) (1/2)(a^2+b^2-(a^2-b^2)cos2alpha)

Evaluate: ((a)/(2b) + (2b)/(a))^(2)- ((a)/(2b)- (2b)/(a))^(2)- 4

(a+2b)^2-(a-2b)^2 is equal to: (a+2b)^2-(a-2b)^2 का मान है :

Evaluate : (iii) ((a)/(2b ) + (2b )/( a) ) ( ( a)/( 2b ) - (2b)/( a))

Evaluate ((a)/(2b)+(2b)/(a))^(2)-((a)/(2b)-(2b)/(a))^(2)-4 .