9. The elastic potential energy of a stretched spring is given by E = 50x2 where x is the displacement in meter and E is in joule, then the force constant of the spring is a. 50 Nm b. 100 Nm c. 100 N/m2 d. 100 Nm 11. 10 am

The elastic potential enegry of a stretched spring is given by E = 50 x^(2) . Where x is the displacement in meter and and E is in joule, then the force constant of the spring is

(a) What is elastic potential energy of a spring ? Obtain the relation for elastic P.E. U=(1)/(2)kx^(2) . Where k is force constant of spring, x is extension or compression produced in the spring.

The potential energy of a spring pendulum, with a mass m connected to it, is given by V=1/2kx^(2) (where x = displacement from the position of equilibrium and k = a constant). How does the applied force on the mass vary with displacement?

An oscillating mass spring system has mechanical energy 1 joule, when it has an amplitude 0.1m and maximum speed of 1ms^(-1) . The force constant of the spring is (in Nm^(-1))

Define elastic potential energy. An elastic spring of force constant k is compressed by an amount x. Show that its pulenlial energy is 1/2 kx^2

Draw a plot of spring force versus displacement x. Hence find an expression for the P.E. of an elastic stretched spring.

A spring gets compressed when a body of mass 5 g is dropped on it from a height of 2 m . Calculate the maximum distance s through whichthe spring is compressed. The force constant of spring is 100 Nm^(-1) .

A long elastic spring is stretched by 2 cm and its P.E. is 20 J. If the spring is stretched by by 10 cm, then its potential energy will be

Force constant of a spring is 100 N//m . If a 10kg block attached with the spring is at rest, then find extension in the spring. ( g= 10 m//s^(2) )