cot^(-1)((ab+1)/(a-b))+cot^(-1)((bc+1)/(b-c))+cot^(-1)((ca+1)/(c-a))=pi

Prove that: cot^(-1)((ab+1)/(a-b))+cot^(-1)((bc+1)/(b-c))+cot^(-1)((ca+1)/(c-a))=0

Prove that: cot^(-1)((ab+1)/(a-b))+cot^(-1)((bc+1)/(b-c))+cot^(-1)((ca+1)/(c-a))=0 .

Prove that : cot^(-1)((1+ab)/(a-b))+cot^(-1)((1+bc)/(b-c))+cot^(-1)((1+ca)/(c-a))=pi,(a>b>c>0)

Prove that : cot^(-1)((1+ab)/(a-b))+cot^(-1)((1+bc)/(b-c))+cot^(-1)((1+ca)/(c-a))=pi,(a>b>c>0)

If a > b > c >0 , prove that cot^(-1)((a b+1)/(a-b))+cot^(-1)((b c+1)/(b-c))+cot^(-1)((c a+1)/(c-a))=pi

If a > b > c >0 , prove that cot^(-1)((a b+1)/(a-b))+cot^(-1)((b c+1)/(b-c))+cot^(-1)((c a+1)/(c-a))=pi

If ab gt -1, bc gt -1 and ca gt -1 , then the value of cot^(-1) ((ab+1)/(a-b) ) + cot^(-1) ((bc+1)/(b-c) ) + cot^(-1) ((ca+1)/( c-a)) is a) -1 b) cot^(-1) "" (a+b+c) c) cot^(-1) ("abc") d)0

Prove the followings : "cot"^(-1)(ab+1)/(a-b)+"cot"^(-1)(bc+1)/(b-c)+"cos"^(-1)(ca+1)/(c-a)=pi(agtbgtc)

If a gt b gt c gt0 , then prove that cot^(-1) ((ab+1)/( a-b)) + cot^(-1) ((bc + 1)/( b-c)) + cot^(-1) ((ca + 1)/( c.-a)) = 0

Prove that for 0 cot^-1 (1+ab)/(a-b) + cot^-1 (1+bc)/(b-c) + cot^-1 (1+ca)/(c-a) = pi