A tent consists of a frustum of a cone, surmounted by a cone. If the diameters of the upper and lower and circular ends of the frustum be 14 m and 26 m respectively, the height of the frustum be 8 m and the slant height of the surmounted conical portion be 12 m, find the area of the canvas required to make the tent. (Assume that the radii of the upper circular end of the frustum and the base of the surmounted conical portion are equal).

Answer

`892.6 m^(2)`

Explanation

`R=12m, r=7 m " and " h=8 m`,
`:." "l=sqrt(h^(2)+(R-0r)^(2))=10m`.
Required area
`={22/7xx10xx(13+7)+22/7xx7xx12}m^(2)`