A right circular cone is divided into three parts by trisecting its height by two planes drawn parallel to the base. Show that the volumes of the three portions starting from the top are in the ratio 1 : 7: 19.

The height of a right circular cone is trisected by two planes drawn parallel to the base. Show that the volumes of the three portions starting from the top are in the ratio 1:7:19.

A solid right circular cone is cut into two parts at the middle of its height by a plane parallel to its base . The ratio of the volume of the smaller cone to the whole cone is

A cone is divided in to two parts by drawing a plane through the mid point of its adis parallel to its base. Compare the volume of two parts.

A solid right circular cone is cut into two parts at the middle of its height by a plane parallel to its base.The ratio of the volume of the smaller cone to the whole cone is: 1:2 (b) 1:4 (c) 1:6 (d) 1:8

A cone of radius r сm and height h cm is divided into two parts by drawing a plane through the middle point of its height and parallel to the base. What is the ratio of the volume of the original cone to the volume of the smaller cone?

A cone of radius r сm and height h cm is divided into two parts by drawing a plane through the middle point of its height and parallel to the base. What is the ratio of the volume of the original cone to the volume of the smaller cone?

A solid cone of base radius 10 cm is cut into two parts through the mid-point of its height, by a plane parallel to its base. Find the ratio in the volumes of two parts of the cone.

If a cone of radius 10cm is divided into two parts by drawing a plane through the mid- point of its axis,parallel to its base.Compare the volumes of the two parts.

A right circular cone is divided into two portions by a plane parallel to the base and passing through a point which is (1)/(3)rd of the height from the top.The ratio of the volume of the smaller cone to that of the remaining frustum of the cone is (a) 1: 3(b) 1: 9 (c) 1:26 (d) 1:27