The height of a conical tent is 14 m and its floor area is 346.5 `m^2` . How much canvas , 1.1 m wide , will be required for it

Options

A. 490 m
B. 525 m
C. 665 m
D. 860 m

Answer

B

Explanation

`piR^2=346.5 rArr R^2=((3465/10 xx 7/22)=(441)/(4)=((21)/(2)^2 rArr =(21)/(2) m`
`l=sqrt(R^2+h^2)=sqrt(441/4+(14)^2)=sqrt((1225)/(4))=(35)/(2)m`
Area of canvas `=piRl=(22/7xx21xx2xx35/2)m^2=577.5 m^2`
Length of canvas `=("area"/"wight ")=(577.50)/(1.1)m=525 m `