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A hollow metallic sphere with external d...

A hollow metallic sphere with external diameter 8 cm and internal diameter 4 cm is melted and moulded into a cone having base radius 4 cm. The height of the cone is

A

12 cm

B

14 cm

C

15 cm

D

18 cm

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To solve the problem step by step, we need to find the height of the cone formed by melting a hollow metallic sphere. ### Step 1: Calculate the volume of the hollow metallic sphere. The volume of a hollow sphere can be calculated by finding the volume of the outer sphere and subtracting the volume of the inner sphere. 1. **External diameter of the sphere** = 8 cm Therefore, the external radius \( R = \frac{8}{2} = 4 \) cm. 2. **Internal diameter of the sphere** = 4 cm Therefore, the internal radius \( r = \frac{4}{2} = 2 \) cm. 3. **Volume of the outer sphere**: \[ V_{\text{outer}} = \frac{4}{3} \pi R^3 = \frac{4}{3} \pi (4)^3 = \frac{4}{3} \pi (64) = \frac{256}{3} \pi \, \text{cm}^3 \] 4. **Volume of the inner sphere**: \[ V_{\text{inner}} = \frac{4}{3} \pi r^3 = \frac{4}{3} \pi (2)^3 = \frac{4}{3} \pi (8) = \frac{32}{3} \pi \, \text{cm}^3 \] 5. **Volume of the hollow sphere**: \[ V_{\text{hollow}} = V_{\text{outer}} - V_{\text{inner}} = \frac{256}{3} \pi - \frac{32}{3} \pi = \frac{224}{3} \pi \, \text{cm}^3 \] ### Step 2: Set the volume of the cone equal to the volume of the hollow sphere. The volume of the cone is given by the formula: \[ V_{\text{cone}} = \frac{1}{3} \pi r^2 h \] where \( r \) is the radius of the base of the cone and \( h \) is the height of the cone. 1. **Given**: Base radius of the cone \( r = 4 \) cm. 2. **Volume of the cone**: \[ V_{\text{cone}} = \frac{1}{3} \pi (4)^2 h = \frac{1}{3} \pi (16) h = \frac{16}{3} \pi h \, \text{cm}^3 \] ### Step 3: Equate the volumes and solve for height \( h \). Set the volume of the cone equal to the volume of the hollow sphere: \[ \frac{16}{3} \pi h = \frac{224}{3} \pi \] 1. **Cancel \( \pi \) and \( \frac{1}{3} \)** from both sides: \[ 16h = 224 \] 2. **Solve for \( h \)**: \[ h = \frac{224}{16} = 14 \, \text{cm} \] ### Final Answer: The height of the cone is **14 cm**. ---

To solve the problem step by step, we need to find the height of the cone formed by melting a hollow metallic sphere. ### Step 1: Calculate the volume of the hollow metallic sphere. The volume of a hollow sphere can be calculated by finding the volume of the outer sphere and subtracting the volume of the inner sphere. 1. **External diameter of the sphere** = 8 cm Therefore, the external radius \( R = \frac{8}{2} = 4 \) cm. ...
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RS AGGARWAL-VOLUME AND SURFACE AREAS OF SOLIDS-Multiple Choice Questions (Mcq)
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  2. The radii of two cylinders are in the ratio 2:3 and their heights are ...

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  3. Two circular cylinderical of equal volumes have their height in the ra...

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  4. The radius of the base of a cone is 5 cm and ir=ts heights is 12 cm . ...

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  5. The diameter of the base of a cone is 42 cm and its volume is 12936 cm...

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  6. The area of the base of a right circular cone is 154 cm^2 and its heig...

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  7. On increasing each of the radius of the base and the height of a cone...

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  8. The radii of the base of a cylinder and a cone are in the ratio 3:4 . ...

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  9. A metallic cylinder of radius 8 cm and height 2 cm is melted and conve...

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  10. The height of a conical tent is 14 m and its floor area is 346.5 m^2 ....

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  11. The diameter of a sphere is 14 cm. Its volume is

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  12. The ratio between the volumes of two spheres is 8 : 27. What is the ra...

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  13. A hollow metallic sphere with external diameter 8 cm and internal diam...

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  14. A metallic cone having base radius 2.1 cm and height 8.4 cm is melted ...

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  15. The volume of a hemisphere is 19404 cm^3. The total surface area of th...

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  16. Find the volume of a sphere whose surface area is 154 cm^(2)

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  17. The total surface area of a hemisphere of radius 7 cm is

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  18. If the radii of the circular ends of a bucket of height 40 cm are of...

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  19. If the radii of the circular ends of a bucket 24 cm high are 5 cm a...

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  20. A circus tent is cylindrical to a height of 4 m and conical above it...

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