Find the derivative of `(9x^(2) + 3/x+ 5 sinx)` with respect to x.

Explanation

We have `d/(dx) (9x^(2) + 3/x + 5 sin x)`
`= 9.(d)/(dx) (x^(2)) + 3.(d)/(dx) (x^(-1)) + 5.d/(dx) (sin x)`
`= 9 xx 2x +3 .(-1) x^(-2) + 5 cos x = 18x - 3/(x^(2)) + 5 cos x`.