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x^(3) -2x^(2) +x+3...

`x^(3) -2x^(2) +x+3`

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To differentiate the function \( y = x^3 - 2x^2 + x + 3 \), we will apply the rules of differentiation step by step. ### Step 1: Write down the function We start with the function: \[ y = x^3 - 2x^2 + x + 3 \] ### Step 2: Differentiate each term We will differentiate each term of the function separately. 1. **Differentiate \( x^3 \)**: \[ \frac{d}{dx}(x^3) = 3x^{3-1} = 3x^2 \] 2. **Differentiate \( -2x^2 \)**: \[ \frac{d}{dx}(-2x^2) = -2 \cdot 2x^{2-1} = -4x \] 3. **Differentiate \( x \)**: \[ \frac{d}{dx}(x) = 1 \] 4. **Differentiate the constant \( 3 \)**: \[ \frac{d}{dx}(3) = 0 \] ### Step 3: Combine the derivatives Now, we combine all the derivatives we calculated: \[ \frac{dy}{dx} = 3x^2 - 4x + 1 + 0 \] Thus, we simplify it to: \[ \frac{dy}{dx} = 3x^2 - 4x + 1 \] ### Final Answer The derivative of the function \( y = x^3 - 2x^2 + x + 3 \) is: \[ \frac{dy}{dx} = 3x^2 - 4x + 1 \] ---
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