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lim(z->1)(z^(1/3)-1)/(z^(1/6)-1)...

`lim_(z->1)(z^(1/3)-1)/(z^(1/6)-1)`

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Given `(lim)_(z->1)(z^(1/3)-1)/(z^(1/6)-1)`
Both numerator and denominator are divided by `(z-1)`
=`(lim)_(z->1)((z^(1/3)-1)/(z-1))/((z^(1/6)-1)/(z-1))`
Since we know that `lim_(x->a)((x^n-a^n)/(x-a))=na^(n-1)`
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