Find the power of a person who can chew `30g` of ice in one minute. Latent heat of ice `=80cal//gm`, `J=4.2`joule `//` cal.

Power of a man who can chew 0.3 kg ice in one minute is (in cal/s).

What power is gained by a man when he eats 100 g ice in one minute ? Latent heat of fusion of ice is 80 cal/gm.

The entropy change in melting 1g of ice at 0^@C . (Latent heat of ice is 80 cal g^(-1) )

Find the heat required to convert 1 g of ice at 0°0C to vapour at 100°C. (Latent heat of ice = 80 cal/g and latent heat of vapour = 536 cal/g)

What is the horse power applied by a person while chewing 100g of ice per minute ? Given J = 4.2 joule per calorie.

What is the meant by the statement, 'Latent heat of fusion of ice is 80cal/gm ?

Calculate the horse power of a man who can chew ice at the rate of 60g min.^(-1) . Given J = 4.2 J cal^(-1) and altent heat of ice = 80 cal g^(-1), 1hp = 746W .