`f:[-2,2] rarr R` is defined as `f(x)={-1,-2 <= x <= 0 x-1,0 <= x <= 2` then `{x in[-2,2]:x <= 0 f(|x|)=x}=`

If f:[-2,2]rarr R is defined by f(x)={-1 for -2<=x<=0, then x-1, for 0<=x<=2[x in[-2,2]:x<=0 and f(|x|)=bar(x)}=

The function f:R rarr R is defined by f(x)=(x-1)(x-2)(x-3) is

Let f : R - {2} rarr R be defined as f(x) = (x^2 - 4)/(x-2) and g: R rarr R be defined by g(x) = x + 2. Find whether f = g or not.

f:R rarr Rf:R rarr R is defined by f(x)=x^(2)-3x+2 find

f:R rarr R defined by f(x)=x^(2)+5

If f:R rarr R is defined by f(x)=3x-2 then f(f(x))+2=

Let f:R-{2}rarr R be defined as f(x)=(x^(2)-4)/(x-2) and g:R rarr R be defined by g(x)=x+2. Find whether f=g or not.

If f : R rarr R is defined by f(x)=x^2+2 and g : R-{1} rarr R is defined by g(x)=x/(x-1) , find (fog)(x) and (gof)(x) .

Let f:R rarr R is defined by f(x)=3x-2 and g:R rarr R is defined by g(x)=(x+2)/3 . Show that f.g=g.f .