[" (i) "a^(4)-b^(4)," (ii) "p^(4)-81],[" (iv) "x^(4)-(x-z)^(4)," (v) "a^(4)-2a^(2)b^(2)+b^(4)]

Factorise. (i) a^4 - b^4 (ii) p^4 - 81 (iii) x^4-(y+z)^4 (iv) x^4-(x-z)^4 (v) a^2-2a^2b^2 + b^4

Factorise. (i) a^4 - b^4 (ii) p^4 - 81 (iii) x^4-(y+z)^4 (iv) x^4-(x-z)^4 (v) a^2-2a^2b^2 + b^4

Factorize: x^(4)-y^(4) (ii) 16x^(4)-81x^(4)-(y+z)^(4)( iv )2x-32x^(5)3a^(4)-48b^(4)(vi)81x^(4)-121x^(2)

Factorize: 4x^(2)+12xy+9y^(2)(ii)x^(4)-10x^(2)y^(2)+25y^(4)a^(4)-2a^(2)b^(2)+b^(4)

Factorize: (a^(4)-8a^(2)b^(2)+16b^(4))-256a^(4)-6a^(2)b^(2)+9b^(4)-81

Factorize each of the following algebraic expressions: x^(4)-81y^(4) (ii) 2x^(5)-2x3x^(4)-243( iv )2-50x^(2)x^(8)-y^(8)( vi )a^(12)x^(4)-a^(4)x^(12)

By how much is a^(4)+4a^(2)b^(2)+b^(4) more than a^(4)-8a^(2)b^(2)+b^(4)

Factorize following expressions (i) a^2-4a+3+2b-b^2" (ii)" x^(4)+324" (iii)"x^4-y^2+2x^2+1 (iv) 4a^4-5a^2+1" (v)"x^6-7x^2-6

Use the identity (x+a)(x+b)=x^2+(a+b)x+ab to find the following products. (i) (x+3)(x+7) (ii) (4x+5)(4x+1) (iii) (4x+5)(4x+1) (iv) (4x+5)(4x-1) (v) (2x+5y)(2x+3y) (vi) (2a^2+9)(2a^2+5) (vii) (xyz-4)(xyz-2)