If ` vec a , vec ba n d vec c` are unit vectors, then `| vec a- vec b|^2+| vec b- vec c|^2+| vec c- vec a|^2` does not exceed `4` b. `9` c. `8` d. `6`

If vec a, vec b, vec c are unit vectors then |vec a - vec b|^(2) + |vec b - vec c|^(2) + |vec c - vec a|^(2) does not exceed.

If vec a , vec b , vec c are unit vector, prove that | vec a- vec b|^2+| vec b- vec c|^2+| vec c- vec a|^2lt=9.

If vec a,vec b and vec c are unit vectors,then |vec a-vec b|^(2)+|vec b-vec c|^(2)+|vec c-vec a|^(2) does not exceed 4 b.9c.8 d.6

If vec a,vec b,vec c are unit vector,prove that |vec a-vec b|^(2)+|vec b-vec c|^(2)+|vec c-vec a|^(2)<=9

If vec a , vec ba n d vec c are unit vectors satisfying | vec a- vec b|^2+| vec b- vec c|^2+| vec c- vec a|^2=9, then |2 vec a+5 vec b+5 vec c| is.

If vec a , vec ba n d vec c are unit vectors satisfying | vec a- vec b|^2+| vec b- vec c|^2+| vec c- vec a|^2=9, then |2 vec a+5 vec b+5 vec c| is.

If vec a , vec ba n d vec c are unit vectors satisfying | vec a- vec b|^2+| vec b- vec c|^2+| vec c- vec a|^2=9, then |2 vec a+5 vec b+5 vec c| is.

If vec a , vec ba n d vec c are unit vectors satisfying | vec a- vec b|^2+| vec b- vec c|^2+| vec c- vec a|^2=9, then |2 vec a+5 vec b+5 vec c| is.

If vec a , vec ba n d vec c are unit coplanar vectors, then the scalar triple product [2 vec a- vec b2 vec b- vec c2 vec c- vec a] is 0 b. 1 c. -sqrt(3) d. sqrt(3)

If vec a , vec ba n d vec c are unit coplanar vectors, then the scalar triple product [2 vec a- vec b2 vec b- vec c2 vec c- vec a] is a. 0 b. 1 c. -sqrt(3) d. sqrt(3)