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If one end of a diameter of the circle `x^(2)+y^(2)-4x-6y+11=0` is (3, 4), then find the coordinates of the other end of the diameter.

A

(2,1)

B

(1,2)

C

(1,1)

D

None of these

Text Solution

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The correct Answer is:
B
The centre of the given circle `x^(2)+y^(2)-4x-6y+11=0 is (2,3).`
let the other end of diameter be `(x_1,y_1)`.
since, centre
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