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Find the greatest distance of the point `P(10 ,7)` from the circle `x^2+y^2-4x-2y-20=0`

A

10,5

B

15,20

C

12,16

D

5,15

Text Solution

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The correct Answer is:
D
We have , `10^(2)+7^(2)-4x10-2x7-20=75gt0` so, the point P (10,0) lies outside the circle.
` (##ARH_EGN_PRG_MAT_C05_E01_006_S01.png" width="80%"> Also, centre of given circle is C (2,1) and r =5.
:. Greatest distance = 10+5+15 least distnce =10-5=5
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