If the centre, one of the foci and semi-major axis of an ellipse are (0,0), (0,3) and 5, then its equation is

Options

A. `x^(2)/16+y^(2)/25=1`
B. `x^(2)/25+y^(2)/16=1`
C. `x^(2)/9+y^(2)/25=1`
D. None of these

Answer

A

Explanation

We have, b=5 and bgta since, `c^(2) =b^(2) -a^(2)`
`rArr 9=25-a^(2)`
`rArr a^(2)=16`
`therefore` required equation of ellipse is `x^(2)/16+y^(2)/25=1`