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The foci of the conic section...

The foci of the conic section

A

`(0,+-3)`

B

`(0,+-2)`

C

`(3,+-3)`

D

`(0,+-1)`

Text Solution

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The correct Answer is:
C
Given equation can be rewritten as `(x-3)^(2)/16+y^(2)/25=1`
` Here, `a^(2)=16 and b^(2)=25`
`therefore e=sqrt(1-(16)/(25))=3/5`
` hence, the foci of conic section are `(0,+-be),i.e.(,+-3).`
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