The circle passing through (1, -2) and touching the axis of x at (3, 0) also passes through the point (1) (2, -5) (2) (5, -2) (3) (-2, 5) (4) (-5, 2)

Options

A. `-(5,2)`
B. `-(2,-5)`
C. `(5,-2)`
D. `-(2,5)`

Answer

C

Explanation

Let the equation of cricle be (x-3)^(2)+(y-0)^(2)+lamday=0` as, it passes through (1,-2).
`therefore (1-3)^(2)+(y-0)^(2)+lamda(-2)=0`
`rArr 4+4-lamda=0rArrlamda=0`
`therefore` equation of cricle is `(x-3)^(2)+y^(2)+4y=0`by hit and trial method, we see that, point (5,-2)sattisfies equation of cricle.