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The directrix of the parabola y^(2)+4x+...

The directrix of the parabola `y^(2)+4x+3=0`is

A

`x-4/3=0`

B

`x-1/4=0`

C

`x-3/4=0`

D

`x-1/4=0`

Text Solution

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The correct Answer is:
B
Given, `y^(2)=-4(x+3/4)`
y^(2)=-4x, where x=x+3/4andy=y the equation of directrix of parabola is `x=1rArrx+3/4=1rArrx-1/4=0`
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