If the eccentricity of a hyperbola is `sqrt(3)`, the eccentricity of its conjugate hyperbola, is

Options

A. `sqrt2`
B. `sqrt3`
C. `sqrt3/2`
D. `2sqrt3`

Answer

C

Explanation

Let e and e' be the eccentricities of a hyperbola and its conjugate hyperbola. Then, `(1)/(e^(2))+(1)/((e')^(2))=1rArr(1)/(3)+(1)/((e')^(2))=1`
`rArre'=sqrt((3)/(2)`