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If f(x) = be^(ax) + ae^(bx) , then f''...

If ` f(x) = be^(ax) + ae^(bx) , ` then f''(0) is equal to

A

0

B

2ab

C

`ab (a + b)`

D

ab

Text Solution

Verified by Experts

The correct Answer is:
C
Given , ` f(x) = be^(ax) + ae^(bx)`
`rArr f'(x) = abe^(ax) + aba^(bx)`
` rArr f''(x) = a^(2) be^(ax) + ab^(2) e^(bx)`
` rArr f'''(0) = a^(2) + a^(2) b + ab^(2) = ab (a + b)` .
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