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If K(sp) (PbSO(4)) =1.8 xx 10^(-8) and K...

If `K_(sp) (PbSO_(4)) =1.8 xx 10^(-8)` and `K_(a) (HSO_(4)^(Theta)) = 1.0 xx 10^(-2)` the equilibrium constant for the reaction.
`PbSO_(4)(s) +H^(o+)(aq) hArr HSO_(4)^(Theta)(aq) +Pb^(2+)(aq)` is

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In atmosphere, SO_(2) and NO are oxidised to SO_(3) and NO_(2) , respectively,w hcih react with water to given H_(2)SO_(4) and HNO_(3) . The resultant solution is called acid rain. SO_(2) dissolves in water to form diprotic acid. SO_(2)(g) +H_(2)O(l) hArr HSO_(3)^(Theta) + H^(o+), K_(a_(1)) = 10^(-2) . HSO_(3)^(Theta) hArr SO_(3)^(2-) + H^(o+), K_(a_(2)) = 10^(-7) and for equilibrium, SO_(2)(aq) + H_(2)O (l) hArr SO_(3)^(2-)(aq) +2H^(o+)(aq) K_(a) = K_(a_(1)) xx K_(a_(2)) = 10^(-9) at 300K . The dominant equilibrium in an aqueous solution of sodium hydrogen sulphite (NaHSO_(3)) is 2HSO_(3)^(Theta) (aq) hArr SO_(2) (aq) +SO_(3)^(2-) (aq) + H_(2)O(l) The equilibrium constant for the above reaction is

In atmosphere, SO_(2) and NO are oxidised to SO_(3) and NO_(2) , respectively,w hcih react with water to given H_(2)SO_(4) and HNO_(3) . The resultant solution is called acid rain. SO_(2) dissolves in water to form diprotic acid. SO_(2)(g) +H_(2)O(l) hArr HSO_(3)^(Theta) + H^(o+), K_(a_(1)) = 10^(-2) . HSO_(3)^(Theta) hArr SO_(3)^(2-) + H^(o+), K_(a_(2)) = 10^(-7) and for equilibrium, SO_(2)(aq) + H_(2)O (l) hArr SO_(3)^(2-)(aq) +2H^(o+)(aq) K_(a) = K_(a_(1)) xx K_(a_(2)) = 10^(-9) at 300K . The dominant equilibrium in an aqueous solution of sodium hydrogen sulphite (NaHSO_(3)) is 2HSO_(3)^(Theta) (aq) hArr SO_(2) (aq) +SO_(3)^(2-) (aq) + H_(2)O(l) The equilibrium constant for the above reaction is