Two circles which pass through the points `A(0, a), B (0,-a)` and touch the line `y = mx+c` wil cut orthogonally if

The condition that the circles which passes through the points (0,a),(0,-a) and touch the line y= mx+c will cut orthogonally is

Prove that the two circles which pass through the points (0,a),(0,-a) and touch the line y=mx+c will cut orthogonally if c^2=a^2(2+m^2)

Prove that the two circles each of which passes through the point (0, k) and (0, -k) and touches the line y=mx+b will cut orthogonally, if b^2 = k^2 (2+m^2) .

The two circles which passes through (0,a) and (0,-a) and touch the line y = mx+c will intersect each other at right angle ,if

The two circles which pass through (0,a)a n d(0,-a) and touch the line y=m x+c will intersect each other at right angle if

The centre of a circle passing through the points (0,0),(1,0)and touching the circle x^2+y^2=9 is

The equation of the circle which passes through the origin has its centre on the line x+y=4 and cuts orthogonally the circle x^2+y^2-4x+2y+4=0

P(a,b) is a point in first quadrant.If two circles which passes through point P and touches both the coordinate axis,intersect each other orthogonally,then