The number of triangles `ABC` that can be formed with `sinA=5/(13), a=3` and `b=8` is

The number of triangles ABC that can be formed with sin A=(5)/(13),a=3 and b=8 is

A triangle ABC in which side AB,BC,CA consist 5,3,6 points respectively, then the number of triangle that can be formed by these points are

In a triangle ABC, the value of sinA+sinB+sinC is

In triangle ABC, a=2, b=3 and sinA=(2)/(3) ,then B is equal to

There are 8 points in a plane, no three of them are collinear .The number of triangles that can be formed is:

If A, B and C are the vertices of a triangle ABC, prove sine formula that =(a)/(sinA)=(b)/(sinB)=(c)/(sinC)

The centroid of the triangle ABC where A= (2,3), B= (8,10) and C= (5,5) is

In triangle ABC , prove that sinA=sin(B+C)

In any triangle ABC, the side are a=7,b=5 and c=8. Find A.

In triangle ABC , prove that a^2sin(B-C)=(b^2-c^2)sinA .