Given `sqrt(4-x^2)>=1/x`, find the interval in which `x` lies.

If log_(2)(x-2)ltlog_(4)(x-2) ,, find the interval in which x lies.

If (y^(2)-5y+3)(x^(2)+x+1)<2x for all x in R, then fin the interval in which y lies.

Let (y^2-5y+3)(x^2+x+1)lt2x for all xepsilonR then the interval in which y lies is (A) ((5-sqrt(5))/2,(5+sqrt(5))/2) (B) (-oo,-2] (C) [-2,-2/3] (D) (1,4)

If x^(2)-1 =0 then x lies in the interval set

Find the solutions of the equation, (log)_(sqrt(2)sin"x")(1+cosx)=2, in the interval x [0,2pi]

Find the value of c, of mean value theorem.when (a) f(x) = sqrt(x^(2)-4) , in the interval [2,4] (b) f(x) = 2x^(2) + 3x+ 4 in the interval [1,2] ( c) f(x) = x(x-1) in the interval [1,2].

If f:RrarrR be a function given f(x)=sqrt1- sqrt(1-x^2) then the domain of the interval _____.

Using Lagrange's theorem , find the value of c for the following functions : (i) x^(3) - 3x^(2) + 2x in the interval [0,1/2]. (ii) f(x) = 2x^(2) - 10x + 1 in the interval [2,7]. (iii) f(x) = (x-4) (x-6) in the interval [4,10]. (iv) f(x) = sqrt(x-1) in the interval [1,3]. (v) f(x) = 2x^(2) + 3x + 4 in the interval [1,2].

(|x|-1)/(|x|-2)<=0 then x lies in the interval

The expression (x^(2)+2x+1)/(x^(2)+2x+7) lies in the interval; (x in R)