Three forces `vecF_(1),vecF_(2)` and `vecF_(3)` are simultaneously acting on a particle of mass `'m'` and keep it in equlibrium. If `vecF_(1)` force is reversed in direction only, the acceleration of the particle will be.

Three forces vecF_(1)=a(hati-hatj+hatk),vecF_(2)=2hati-3hatj+4hatk and vecF_(3)=8hati-7hatj+6hatk act simultaneously on a particle. If the particle is in equilibrium, the value of alpha is

Two forces vecF_(1) and vecF_(2) are acting at right angles to each other, find their resultant ?

If the four forces as shown are in equilibrium Express vecF_(1)& vecF_(2) in unit vector form.

Three forces vecF_(1)=(3hati+2hatj-hatk) dynes, vecF_(2)=(3hati+4hatj-5hatk) dynes and vecF_(3)=a(hati+hatj-hatk) dynes act simultaneously on a particle. What should be the value of 'a' so that the particle may remain in equilibrium?

Three forces vecF_(1)=(3hati+2hatj-hatk) dynes, vecF_(2)=(3hati+4hatj-5hatk) dynes and vecF_(3)=a(hati+hatj-hatk) dynes act simultaneously on a particle. What should be the value of 'a' so that the particle may remain in equilibrium?

Three forces vecF_(1)=(3hati+2hatj-hatk) dynes, vecF_(2)=(3hati+4hatj-5hatk) dynes and vecF_(3)=a(hati+hatj-hatk) dynes act simultaneously on a particle. What should be the value of 'a' so that the particle may remain in equilibrium?