The area of cross section of a steel wire `(Y=2.0 xx 10^(11) N//m^(2))` is `0.1 cm^(2)`. The force required to double is length will be

The area of cross section of a steel wire (Y=2.0xx10^11 N//m^2) is 0.1 cm^2 . The force required to double its length will be

For steel Y=2xx10^(11) Nm^(-2) . The force required to double the length of a steel wire of area 1 cm^(2) is

A wire of length 1m is stretched by a force of 10N. The area of cross-section of the wire is 2 × 10^(–6) m^(2) and Y is 2 xx 10^(11) N//m^(2) . Increase in length of the wire will be -

The area of a cross-section of steel wire is 0.1 cm^(-2) and Young's modulus of steel is 2 x 10^(11) N m^(-2) . The force required to stretch by 0.1% of its length is

The area of a cross-section of steel wire is 0.1 cm^(-2) and Young's modulus of steel is 2 x 10^(11) N m^(-2) . The force required to stretch by 0.1% of its length is

The area of a cross section of steel wire is 0.1cm^2 and Young's modulus of steel is 2xx10^(11)Nm^-2 . The force required to strech by 0.1% of its length is

The area of cross-section of steel wire is 0.1 cm^(2) and Young's modulus of steel is 2 times 10^(11)N" "m^(-1) . The force required to stretched by 0.1% of its length is

A 20 N stone is suspended from a wire and its length changes by 1% . If the Young's modulus of the material of wire is 2xx10^(11)N//m^(2) , then the area of cross-section of the wire is 2xx10^(11)N//m^(2) , then the area of cross-section of the wire will be

The cross-sectional area of a steel rod of length 25 cm is 0.8 cm^(2) . What tension will be required to incresase the length of the rod, equal to the increase due to its rise in temeprature by 10^(@)C ? For steel, Y=2 times 10^(12)dyn*cm^(-2) " and " alpha=10^(-5@)C^(-1) .