" 39.Let ABCDEF be a regular hexagon and "

Let ABCDEF be a regular hexagon and vec AB=vec a,vec BC=vec b,vec CD=vec c then vec AE is

Let ABCDEF be a regular hexagon.If bar(AD)=xBC and bar(CF)=ybar(AB), then xy=a

Let ABCDEF be a regular hexagon If CF=yvec BA then (x+y)^(2)+8 is

Let ABCDEF be a regular hexagon whose centre is at the origin.(A,B,C,D,E and F are in anticlockwise direction).If the coordinates of A be 1+i then c lies in

Let ABCDEF be a regular hexagon with vertices in the anticlockwise sense.If z_(1) and z_(2) represent A and B respectively, the complex number representing C is

In the given figure, ABCDEF is a regular hexagon and angleAOF = 90^(@) . FO is parallel to ED. What is the ratio of the area of the triangle AOF to that of the hexagon ABCDEF?

In the figure shown, ABCDEF is a regular hexagon and AOF is an equilateral triangle. The perimeter of DeltaAOF is 2a feet. What is the perimeter of the hexagon in feet?

If ABCDEF be a regular hexagon then (vec(AD)+vec(EB)+vec(FC)) is equal to -